-(0,04x^2)+9x-350=0

Solution for -(0,04x^2)+9x-350=0 equation:

-(0.04x^2)+9x-350=0

We add all the numbers together, and all the variables

9x-(0.04x^2)-350=0

We get rid of parentheses

-0.04x^2+9x-350=0

a = -0.04; b = 9; c = -350;
Δ = b2-4ac
Δ = 92-4·(-0.04)·(-350)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-5}{2*-0.04}=\frac{-14}{-0.08}
=+175
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+5}{2*-0.04}=\frac{-4}{-0.08}
=+50
$